All get Equal Share

Algebra Level pending

An old and crafty mathematician had n n children, not all of the same sex, none of whom were of the same age. His will was short and sweet. It said :

"My property should be distributed among my children, starting from the eldest to youngest. The i i -th child gets $ 1000 × i + 10 % of what that remains \$1000\times i+ 10\% \mbox{ of what that remains} ."

However, in spite of the apparent inequality in distribution, everyone got an equal share. If all the children gave 0.5 % 0.5 \% of their inheritance as tax. What was the total amount of tax collected from the n n children?

$285 $525 $135 $405

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2 solutions

Murali Kancharla
Jan 24, 2015

I guess it should be 450. 9 children and each gets $10,000. First son gets 1000+10% of 90K=10K 2nd son 1000×2+10% of 80K =10K

So a tax of $50 for each hence $450.

Let the total be 90,000 and 9 children. Then each childs share is 10,000.

1st child gets : 1000 + 10%(90,000-1000) = 1000 + 8900 = 9900 (not 10,000)

Money left after this = 90000-9900 = 80100 2nd child : 2000 + 10%(80100-2000) = 2000 + 7810 = 9810

It is obvious that everyone does not get the same share.

Janardhanan Sivaramakrishnan - 6 years, 4 months ago

Let the total amount of money be T T and the number of children be n n . Then each child's share is T / n T/n .

The first child gets : 1000 + ( T 1000 ) / 10 = T / 10 + 900 1000 + (T-1000)/10 = T/10 +900

Amount left after 1st person's share = T T / 10 900 = 9 / 10 T 900 T-T/10-900 = 9/10T-900

Second child gets : 2000 + ( 9 / 10 T 900 2000 ) / 10 = 9 T / 100 + 1710 2000+(9/10T-900-2000)/10=9T/100+1710

The last child (n-th) gets : 1000 n = T / n 1000n=T/n or n = T 1000 n=\sqrt{\frac{T}{1000}}

All three quantities are equal.

To get T T : T / 10 + 900 = 9 T / 100 + 1710 T/10+900=9T/100+1710 Thus, T = 81000 T=81000 and n = 9 n=9 .

The tax is 0.5% of all shares. Effectively, 0.5% of the total property = 0.5 % × 81000 = 405 0.5\% \times 81000 = \boxed{405}

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