All in unknown

From $\clubsuit \left( \diamondsuit +\heartsuit \right) =\clubsuit \left( \spadesuit +\heartsuit \right)$ you can find out that $\clubsuit =0$ or $\diamondsuit =\spadesuit$ . And you know that $\diamondsuit \neq \spadesuit$ . So $\clubsuit =0$ . Also $\diamondsuit +0=1\quad \Rightarrow \quad \diamondsuit =1$ . And $1\left( \heartsuit +\spadesuit \right) =5\quad \Rightarrow \quad \heartsuit +\spadesuit =5$ . If you check, the only possible value is $\begin{matrix} \heartsuit =3 & \spadesuit =2 \end{matrix}$ . After if you count all you'll get 8.