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A can of volume 1 m 3 1\text{ m}^3 is filled with a hypothetical gas at 300 K 300 \text{ K} and initial pressure 1.0 × 1 0 6 Pa 1.0 \times 10^6 \text{ Pa} . The mass of can is 6 kg 6 \text{ kg} . The can is now kept in a incinerator and heat is supplied to it power 1000 t W/s 1000t \text{ W/s} where t t is in seconds. The 'can' can withstand a maximum pressure of 8.0 × 1 0 6 Pa 8.0 \times 10^6 \text{ Pa} . The specific heat of can is 500 J/(kg.K) 500 \text{ J/(kg.K)} and that of gas is 900 J/(kg.K) 900 \text{ J/(kg.K)} . The coefficient of volumetric expansion of can is 2 × 1 0 5 K 1 2 \times 10^{-5} \text{ K}^{-1} .

Find the time (in seconds to the nearest integer) after which the can will explode. Take molar mass of gas same as that of hydrogen gas and R = 25 / 3 Pa m 3 /(mol K) R=25/3 \text{ Pa m}^3 \text{/(mol K)} .


The answer is 88.

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1 solution

Yaata! i did it .

Congratulations for being the first solver of this problem.

Akshay Yadav - 4 years, 3 months ago

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yes, this Q is just too dangerous :P , did in 3rd trial .

A Former Brilliant Member - 4 years, 3 months ago

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