Find the sum of all ordered triples of positive integers such that each of the following numbers is a power of 2.
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16 such triplets exist: (2,2,2), 3 permutations of (2,2,3), 6 permutations of (2,6,11) and 6 permutations of (3,5,7)
6 + 3 times 7 + 6 times 19 + 6 times 15 = 2 3 1 It took 30 minutes of Trial and Error.....