x 2 + x − 1 2 3 4 5 6 7 8 9 = 0
The equation above has __________ .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
For the quadratic equation A x 2 + B x + C = 0 ,
if B 2 = 4 A C , the roots are equal
if B 2 > 4 A C , the roots are real and distinct
if B 2 < 4 A C , the roots are imaginary or non-real.
x 2 + x − 1 2 3 4 5 6 7 8 9 = 0 ⟹ B 2 > 4 A C ∴ The roots are real and distinct.
Problem Loading...
Note Loading...
Set Loading...
Clearly, the equation above has a discriminant b 2 − 4 a c = 1 + 4 ⋅ 1 2 3 4 5 6 7 8 9 > 0 ⇒ the equation above has two distinct real solutions (roots).