My first Gem!

Algebra Level 4

Is it possible to express 1 2 + 2 2 + 3 2 + + 5 0 2 1^2 + 2^2 + 3^2 + \cdots + 50^2 as p q × q p p^q\times q^p , where p p and q q are positive integers.

If yes then find p + q p+q .

Else submit your answer as 9999 9999


This is an original problem and belongs to the set My creations


The answer is 42926.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Skanda Prasad
Sep 18, 2017

Calculating the sum of the series from the formula for the sum of squares, we get the value to be equal to 42925 42925 .

The only possible way to express 42925 42925 as p q p^{q} × \times q p q^p is ( 1 42925 × 4292 5 1 1^{42925}\times 42925^1 ).

Hence, p + q = 42926 p+q=42926

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...