If we square a 5 digit integer less than 90000, it will be 1 more than a 10-digit integer which contains each of the digits 0, 1, 2, ... , 9. What is this 5 digit integer?
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Actually there are two solutions: 8 5 5 5 5 2 = 7 3 1 9 6 5 8 0 2 4 + 1 and 9 7 7 7 7 2 = 9 5 6 0 3 4 1 7 2 8 + 1 .
I used a java program to generate all squares of such form and looked at them one by one. It was not a tedious task since there is only 9 0 entries.
The code and the list generated is here: http://pastebin.com/N959TE5u
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