y + z x + x + z y + x + y z + 2 x y + y z + x z 2 ( x 2 + y 2 + z 2 )
Let x , y and z be positive reals . If the minimum value of the expression above can be expressed in the form γ α β , where α , β and γ are positive integers with β square-free and α and γ coprime, find α + β + γ .
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y + z x = < 2 y z x and so on in the end we get that the minima is 2 3 + 2 2 and with a little arrangement we get 2 7 2 that gives us the answer 11.