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Calculus Level 5

n = 2 ζ ( n ) 1 n + 2 = C H I ln A C 1 γ K P E ln ( A 1 π ) S \displaystyle\sum _{ n=2 }^{ \infty }{ \dfrac { \zeta (n)-1 }{ n+2 } } =\dfrac { C }{ H } -I\ln { A } -\dfrac { C_{ 1 }\gamma ^{ K } }{ P } -\dfrac { E\ln { (A_{ 1 }\pi ) } }{ S }

The equation holds true, where A A denotes the Glaisher Kinkelin constant and γ \gamma denotes the Euler-Mascheroni constant .

And C , H , I , C 1 , K , P , E , A 1 , S C,H,I,C_1,K,P,E,A_1,S are positive integers with gcd ( C , H ) = gcd ( C 1 , P ) = gcd ( E , S ) = 1 \gcd(C,H)=\gcd(C_1,P)=\gcd(E,S)=1 .

Find C + H + I + C 1 + K + P + E + A + S C+H+I+C_1+K+P+E+A+S .


The answer is 29.

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