Alpha and beta .

Chemistry Level pending

when 90 T h 234 {}_{90}Th^{234} disintegrates to give 82 P b 206 {}_{82}Pb^{206} . the number of α \alpha particles be x x & no of β \beta paricles be y y find 10 x + y 10x+y .


The answer is 76.

Shriram Lokhande by Shriram Lokhande , 21, India

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1 solution

Shriram Lokhande
Aug 5, 2014

90 T h 234 → 82 P b 206 + x 2 H e 4 + y − 1 e 0 {}_{90}Th^{234} \rightarrow {}_{82}Pb^{206} + x{}_{2}He^{4}+y{}_{-1}e^0 Equating mass number on both sides , we get 234 = 206 + 4 x + 0 y ⇒ x = 7 234=206+4x+0y \Rightarrow x=7 Equating atomic number on both sides , we get 90 = 82 + 2 x − y ⇒ y = 6 90=82+2x-y \Rightarrow y=6 Therefore we get our answer as 76 \boxed{76}

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