Alternating Current Series #4

The circuit as shown consists of two identical sections $A$ and $B$ , each of them is a parallel combination of a capacitor of capacitance $C$ and an inductor of inductance $L$ .

Initially the voltage of capacitor in the section $A$ is $V_0$ the capacitor in the section $B$ has no charge and none of the inductors carry current. When voltage on the capacitor in section $A$ drops to half of its initial value, the switch is closed. Find the maximum current through the inductor of section $B$ after the switching.

The answer is in the form of $I_{max}=\alpha V_{0} \sqrt{\dfrac{C}{L}}$ . Submit $\alpha$ .

The problem is taken from my Physics Book.