Always had a desire to fly kite with sos
I am flying a kite. The kite is moving horizontally at
above the ground. If the speed of the kite is
. How fast
(in m/s)
is the string being let out,when the kite is
from me ?
(assuming my height to be
) ?
Try for some more interesting problems of Limits and Derivatives.
The answer is 8.
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1 solution
Assume the kite's String makes an angle of 'theta' with the horizontal. Now the rt tr has height = 150; hypotenuse= 250 hence base = 200. Now since the string is taut therefore velocity along the string is same hence velocity of string is the velocity of kite along the string i.e. vcos(theta) = 10(200/250) =8(Answer)