AM-GM..... Huh?

Algebra Level 3

Find the minimum value of 4 x 3 + 1 x 12 4x^3+\dfrac{1}{x^{12}} where x R + x \in \mathbb{R_+} .

Bonus: Find the value of x x for which the expression has a minimum value.


The answer is 5.

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1 solution

Rishabh Jain
Apr 2, 2016

Let expression be T \large\color{#20A900}{\mathfrak T} which can be written as:

x 3 + x 3 + x 3 + x 3 + 1 x 12 By AM GM \large\underbrace{\color{#D61F06}{x^3+x^3+x^3+x^3}+\dfrac{1}{x^{12}}}_{\color{#EC7300}{\text{By AM }\geq \text{ GM}}}

T 5 ( 1 ) 1 / 5 = 5 \Large \color{#20A900}{\mathfrak T}\geq 5(1)^{1/5}=\color{#302B94}{\boxed{5}}


Equality occurs when x 3 = 1 x 12 x^3=\dfrac{1}{x^{12}} or x = 1 \color{#3D99F6}{x=1}

Has there ever been a case when I post an algebra question and you don't write a solution to it? Anyway, upvoted!!

Rishik Jain - 5 years, 2 months ago

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Yep, he's kinda solution master.

Aditya Sky - 5 years, 2 months ago

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Rishabh Jain - 5 years, 2 months ago

Haha... Thanks... :-)

Rishabh Jain - 5 years, 2 months ago

I was about to post the same solution ! :)

Aditya Sky - 5 years, 2 months ago

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Great .... :-) ..... Anyway I did your job.... :-)

Rishabh Jain - 5 years, 2 months ago

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