am
A dam is situated at a height of 550 m above sea level and supplies water to a power house which is at a height of 50 m above sea-level. 2000 kg of water passes through the turbines per second. What would be the maximum electrical power output of the power house if the whole system were 80% efficient ?
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1 solution
Power is in Watts, not Volts. This station could put out 8 million Volts at one Amp or 1 Volt at 8 million Amps...
P = p×q×g×h (rounding density and g)
=1000g/m^3 × 2m^3/s × 10m/s^2 × 500
=10 000 000 WATTS = 10MW
×0.8 efficiency = 8MW