Amazed At The Expression? Even I was too

Geometry Level 4

k = 1 100 ( 1 + 2 cos ( 2 π 3 k 3 100 + 1 ) ) = ? \large\prod^{100}_{k=1} \left(1+2\cos\left(\frac{2\pi \cdot 3^k}{3^{100}+1}\right)\right)= ?


The answer is 1.

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2 solutions

Aditya Kumar
Jul 7, 2017

For a hint use the fact that (2cos2A +1) = sin(3A)/sinA.

Can you derive the fact?

Md Zuhair - 3 years, 11 months ago

using componendo dividendo

Sidharth Nair - 3 years, 10 months ago
Hana Wehbi
Jul 7, 2017

At some point the cos \cos function is gonna go to zero, so we end up with the product of ones which gives an answer of 1 1 .

The above product can be split into the sum of two products. Now, for the product of cosines, we know for some k k , we are going to have the value of c o s = 0 cos = 0 , then the whole product is 0 0 too because there is one term which is 0 0 . The remaining is product of 1 s 1s which is 1 1

Can you please justify your statement?

Md Zuhair - 3 years, 11 months ago

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