Amazing Polynomial!

Algebra Level 5

The polynomial P ( x ) = x 3 + a x 2 + b x + c P(x) = x^3 + ax^2 + bx + c has the property that the mean of its zeros, the product of its zeros, and the sum of its coefficients are all equal. If the y y -intercept of the graph of y = P ( x ) y = P(x) is 2, then what is the value of b ? -b?


The answer is 11.

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2 solutions

mean of it's zeros = - a/3 = the product of it's zeros = - c =sum of its coefficients = 1+a+b+c.
y-intercept of the graph means x=0. So P(0)= 2 =c.
Means - 2 = - c = - a/3 = 1+a+b+c. Solving, -b = 11.

Damn my silly arithmetic mistakes! :(

Prasun Biswas - 6 years, 5 months ago
Daniel Ferreira
Jan 31, 2015

Condição I:

x + x + x 3 = x x x = 1 + a + b + c \frac{x' + x'' + x'''}{3} = x' \cdot x'' \cdot x''' = 1 +a + b + c

Condição II:

P ( 0 ) = 2 P(0) = 2

Por conseguinte, c = 2 \boxed{c = 2}

Das relações de Girard,

x + x + x = a 1 x' + x'' + x''' = - \frac{a}{1}

E,

x x x = c 1 x' \cdot x'' \cdot x''' = - \frac{c}{1}

Substituindo-as na condição I:

{ a 3 = 2 2 = 1 + a + b + 2 \begin{cases} \frac{- a}{3} = - 2 \\\\ - 2 = 1 + a + b + 2\end{cases}

Encontremos "a",

a = 2 3 a = 6 - a = - 2 \cdot 3 \\ \boxed{a = 6}

Por fim,

2 = 3 + a + b 2 = 3 + 6 + b b = 11 - 2 = 3 + a + b \\ - 2 = 3 + 6 + b \\ \boxed{\boxed{- b = 11}}

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