The polynomial P ( x ) = x 3 + a x 2 + b x + c has the property that the mean of its zeros, the product of its zeros, and the sum of its coefficients are all equal. If the y -intercept of the graph of y = P ( x ) is 2, then what is the value of − b ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Damn my silly arithmetic mistakes! :(
Condição I:
3 x ′ + x ′ ′ + x ′ ′ ′ = x ′ ⋅ x ′ ′ ⋅ x ′ ′ ′ = 1 + a + b + c
Condição II:
P ( 0 ) = 2
Por conseguinte, c = 2
Das relações de Girard,
x ′ + x ′ ′ + x ′ ′ ′ = − 1 a
E,
x ′ ⋅ x ′ ′ ⋅ x ′ ′ ′ = − 1 c
Substituindo-as na condição I:
⎩ ⎪ ⎨ ⎪ ⎧ 3 − a = − 2 − 2 = 1 + a + b + 2
Encontremos "a",
− a = − 2 ⋅ 3 a = 6
Por fim,
− 2 = 3 + a + b − 2 = 3 + 6 + b − b = 1 1
Problem Loading...
Note Loading...
Set Loading...
mean of it's zeros = - a/3 = the product of it's zeros = - c =sum of its coefficients = 1+a+b+c.
y-intercept of the graph means x=0. So P(0)= 2 =c.
Means - 2 = - c = - a/3 = 1+a+b+c. Solving, -b = 11.