Amazing Trigonometry_3

Geometry Level 4

If cos ( α 3 θ ) cos 3 θ = sin ( α 3 θ ) sin 3 θ = m \dfrac { \cos { (\alpha -3\theta ) } }{ { { \cos }^{ 3 }\theta } } =\dfrac { \sin { (\alpha -3\theta ) } }{ { \sin }^{ 3 }\theta } = m , then find the value of m 2 + m cos α { m }^{ 2 }+m\cos { \alpha } .


This problem is a part of this set .


The answer is 2.

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1 solution

Yashas Ravi
Apr 26, 2019

Assume α = 0 α = 0 for simplicity. Then, the expression becomes:

Since you can replace s i n ( θ ) sin(θ) with c o s ( θ ) cos(θ) , s i n ( θ ) = c o s ( θ ) sin(θ)=cos(θ) so θ = 45 θ=45 degrees. Then, substitute 45 45 degrees for θ θ and 0 0 for α α into one of the equal expressions in the problem to get m = 2 m=-2 . Since we assumed α = 0 α = 0 , c o s ( α ) = 1 cos(α)=1 so the answer is ( 2 ) 2 2 ( 1 ) = 2 (-2)^2 -2(1) = 2 which is the final answer.

U just can't do that

Abhinav Shripad - 1 year, 4 months ago

Great now prove that this will be true for all , although this a very fine trick to do in competitive exams

Hitesh Yadav - 10 months, 3 weeks ago

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