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Classical Mechanics Level 3

A solid initially at 20 ∘ C 20\ ^\circ\text{C} is heated. The graph shows variation in temperature with the amount of heat energy supplied to it. Now, if the specific heat capacity of the solid is 2 J g − 1 ∘ C − 1 , 2\text{ J}{g}^{-1}\ ^\circ\text{C}^{-1}, calculate

(i) the mass of the solid and
(ii) the specific latent heat of fusion of the solid.

Submit your answer as the sum of (i) (in grams) and (ii) ( ( in J/g ) . \text{ J/g}).


The answer is 160.5.

Ashish Menon by Ashish Menon , 20, India

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1 solution

Ashish Menon
Apr 7, 2016

Relevant wiki: Heat Transfer

In part A B AB of the graph,
Heat required = 40 J 40J .
Change in temperature = 40 ° C 40°C .
Using formula, H = m × c × θ R H = m × c × {\theta}_R , 40 = m × 2 × 40 m = 1 2 m = 0.5 g 40 = m × 2 × 40\\ m = \dfrac{1}{2}\\ m = 0.5g


In part B C BC of the graph,
Heat required = ( 120 − 40 ) J = 80 J (120 - 40)J = 80J
We know that m = 0.5 g 0.5g (above). Using formula, H = m × L H = m × L ,
80 = 0.5 × L L = 80 0.5 L = 160 J / g 80 = 0.5 × L\\ L = \dfrac{80}{0.5}\\ L = 160J/g

∴ \therefore The required answer is 0.5 + 160 0.5 + 160 = 160.5 160.5 .

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