An algebra problem by A Former Brilliant Member
2 2 x 2 − 1 0 x + 3 + 6 x 2 − 5 x + 1 ≥ 3 2 x 2 − 1 0 x + 3
The set of values of x for which above inequality holds is given by:
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3 solutions
Good solution
X^2 -5X + 1 =T.
SO THE EXPRESSION BECOMES
2^(2T+1) + 6^T >3^(2T+1)
WHEN U FACTORIZEIT BECOMES
{(2^(2T+1)+3^(2T+1))(2^T-3^T)}>0
first EXPRESSION is always greater than zero.when u solve the second expression u get the solution.(use logs)
quickly , thats my soultion x>=- 2.5 log 3, i will try again iam newly in math
Factorization is WRONG although the conclusion is correct!
X^2-5x+1 =a and solve it by using log then we get an equality and solve it