Distinct Primes

Algebra Level pending

If ( a , b ) (a,b) is the solution of the pair of linear equations 307 x + 308 y = 1 307x+308y = 1 and 308 x + 307 y = 1 308x+307y = 1 , then find the number of distinct prime divisors of 2 a + b \dfrac2{a+b} .

1 None of these 2 4 0 6 5

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1 solution

Abhiram Rao
Mar 25, 2016
  • Verifying the above pair of linear equations , we know that the pair has a unique solution( a 1 a 2 \frac{a1}{a2} is not equal to b 1 b 2 \frac{b1}{b2} ) .
  • Solving , we get a=b= 1 615 \frac{1}{615} => a + b a+b = 2 615 \frac{2}{615} => 2 a + b \frac{2}{a+b} = 2 2 / 615 \frac{2}{2/615} => 2 a + b \frac{2}{a+b} = 615
  • Resolving 615 into prime factors , we get => 615 = 41 3 5 41*3*5
  • Therefore , 615 has 3 distinct prime divisors.
  • As there is no option containing 3 in it , the answer is None of these

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