An algebra problem by Abhishek Chopra

$\displaystyle \sum_{i=1}^n$ $n^{3}$ = $\frac {n^2(n+1)^2}{4}$

By substituting 100 in n, we get

$\frac {100^2(100+1)^2}{4}$ = 25502500

Therefore the sum of first 100 natural number is $\boxed{25502500}$

Apply formula( n(n+1)/2)^2