6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 a
If a satisfies the equation above, what is the value of a ?
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What is anyone's understanding is the
A is number of repeats And the other we copy
6^6 repeat six times ( a = 6 )
A x 6^6
6^6 . 6^1 = 6^7
This truth is an a simple example.
3² + 3² + 3² = (Obvius is 27)
But in shape used
A = 3
X = 3²
{A.x}
3² . 3 = 3³ the same 27.
This shape is perfectly right.
1st we take common 6^6. 6^6[1+1+1+1+1+1]=6^a 6^6 [6]=6^a as 6 power 6 is multipling with 6 therefore we shift it on the other side and divide it 6=[6^a] / [6^6] 6= [6^a] [6^-6] base same power will be add 6^1=6^a-6 as the bases are same we take powers 1=a-6 1+6=a a=7 answer
Think of it as if you're multiplying 6^6 by 6. Therefore, it would be the same as 6^6 x 6^1. When you multiply exponents of the same base, you keep the base and just add the exponents to get the final answer. 6 + 1 = 7. So the answer is 6^7
Is it true that x^x + x^x + x^x +.......+ x^x (lets say until y times of x^x) The solution would be (x)(x^(y+1) May i ask why is the above = 6 x 6^6? Thanks
Now I understand! Thank you.
It's may be easier to think in this way that Lets 6=x,
x^6+x^6+x^6+x^6+x^6+x^6 =6x^6 =6.6^6 (x=6) =6^7
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 a l o g ( 6 6 ) + l o g ( 6 6 ) + l o g ( 6 6 ) + l o g ( 6 6 ) + l o g ( 6 6 ) + l o g ( 6 6 ) = l o g ( 6 a ) 6 ∗ l o g ( 6 6 ) = a ∗ l o g 6
a = 3 6
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You can't distribute a logarithm in a sum.
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 a lo g ( 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 ) = lo g 6 a lo g ( 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 ) = a lo g 6
This is the correct way to distribute the logarithm but you cannot solve this problem this way.
Edit:
You can solve it this way but the involvement of logarithm is actually unnecessary.
lo g ( 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 ) = a lo g 6 lo g [ 6 ( 6 6 ) ] = a lo g 6 lo g 6 7 = a lo g 6 7 lo g 6 = a lo g 6 a = 7
That's what I got
I used this way in my mind!
your method is wrong
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i think where bases are same, power got add, right?
the answer is a=12.
36^6=6^a (6^2)^6=6^a 6^12=6^a => a=12 those who said a=7 are wrong.
numerically:
(36)^6=2,176,782,336 (6)^12= 2,176,782,336 6^7= 279,936
thank you.
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6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 3 6 6 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 ( 6 6 ) = 3 6 6
6^6=279936 279936x6 = 1679616 6^8 = 1679616 Answer: a=8
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Just a little correction 6 6 = 4 6 6 5 6
Actually 2 7 9 9 3 6 = 6 7
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 a 6 6 ( 1 + 1 + 1 + 1 + 1 + 1 ) = 6 a 6 6 ( 6 ) = 6 a 6 7 = 6 a a = 7
It was easy to understand your solution to this problem
lieonerdo your solution satisfied me most
Used the same method. Easiest way.Why do people use complicated logs in this??just simply take common.Best method in math is the easiest method
I used this method as well. Easiest method.
I did it in this way
Your solution well understood..
I got a=36. I just don’t see how (1+1...) is the same as (6^6+6^6...) makes no sense.
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 ( 6 6 ) = 6 6 + 1 = 6 7 a is therefore 7
Finally, one example that I could understood.
Thank you, this I get..
This is the Simplest and Correct Answer
X^6 + X^6 + X^6 + X^6 +X^6 +X^6 = 6X^6
When x=6 we have 6 (6^6) = 6^1+6 => a=7 , as per exponential law
6 * 6^6
The exponents are 1 and 6. Adding them,
6 + 1 = 7
Answer: 6^7
There are six sixths to the sixth (try saying that six times fast). If you had just 6+6+6+6+6+6, it would be 6 6. The same concept applies here, making it (6^6) 6, which ultimately results in 6^7. I have to admit, I am baffled by how long it took me to realize this.
6E6=46656 Now 46656[1+1+1+1+1+1]=6^6*6^1=6^7 a=7.....
6^6+6^6+6^6+6^6+6^6+6^6=6^6x6
=6^6x6^1
=6^(6+1)
=6^7
Given : 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 a
let x = 6 6
then: x + x + x + x + x + x = 6 a
6 x = 6 a
6 × 6 6 = 6 a
6 7 = 6 a
7 = a
6^6+6^6+6^6+6^6+6^6+6^6 = 6*6^6 = 6^7
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 1 × 6 6 = 6 1 + 6 = 6 7 → a = 7
The number reapets 6 times.... so,6*6^6=6^7.... now 6^7=6^a as the base is same... so a=7
there are 6 6 6 s, which gives 6 7 , hence a = 7
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 a
6 × 6 6 = 6 a
6 6 + 1 = 6 a
6 7 = 6 a
⇒ a = 7
Using the product of exponents property, 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 × 6 6 = 6 1 × 6 6 = 6 1 + 6 = 6 7 Therefore, a = 7 .
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 × 6 6 = 6 6 + 1 = 6 7
Hence a = 7
6^1+6^1+6^1+6^1+6^1+6^1=6^2
6^2+6^2+6^2+6^2+6^2+6^2=6^3
6^3+6^3+6^3+6^3+6^3+6^3=6^4
6^4+6^4+6^4+6^4+6^4+6^4=6^5 。 。 。
6^n+6^n+6^n+6^n+6^n+6^n=6^n+1
So 6^6+6^6+6^6+6^6+6^6+6^6=6^a, a=6+1=7
6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 ∗ 6 6 = 6 7
First, we can take 6^6 common...afterwards, 6^6 (1+1+1+1+1+1) will remain which after solving, will be 6^6 ×6..we know that on multiplication, powers add up..hence, after adding the powers of 6, we get...6^7=6^a. So, a=7
5+5+5+5+5+5= 5×6=30 Like that 6^6×6^6×6^6×6^6×6^6×6^6=( 6^6)×6=(6^6)×6^1= 6^(6+1)= 6^7
6^6(1+1+1+1+1+1) =6^6(6) =6^7 Therefore a=7
6^6+6^6+6^6+6^6+6^6+6^6=6•6^6=6^7 which is equal to 6^a.So a=7
6^6+6^6+6^6+6^6+6^6+6^6=6^a
=> 6^6 * 6
=> 6^1 + 6^6
=>6^7
a=7
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6 6 + 6 6 + 6 6 + 6 6 + 6 6 + 6 6 = 6 × 6 6 = 6 6 + 1 = 6 7