An algebra problem by Ahmed Essam

here it is:

given that,

$a=12$

$b=14$

$c=84$

so, $84 - (3 \times 12 +2 \times 14 +20$ )

=84 -(36 +28 +20)

= $84 - 84=0$

Given that,

$a = 12$

$b = 14$

$c = 84$

Now,

$84 - (3 \times 12 + 2 \times 14 + 20)$

$= 84 - (36 + 28 + 20)$

$\Rightarrow 84 - 84 =$ $\boxed{0}$

c-(3a+2b+20)
=> 84-(3X12+2X14+20)
=> 84-(36+28+20)
=> 84-84 = 0 Answer 0