An algebra problem by Ajala Singh

Algebra Level 1

What is

2014 × 20132013 2013 × 20142014 ? 2014 \times 20132013 - 2013 \times 20142014?

1 0 2013 2014

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2 solutions

Milind Prabhu
Aug 26, 2014

2014 × 20132013 2013 × 20142014 = 2014 × 2013 × 1001 2013 × 2014 × 1001 = 0 \quad 2014\times 20132013-2013\times 20142014\\ =2014\times 2013\times 1001-2013\times 2014\times 1001\\ = \boxed { 0 }

It should be "10001", not "1001". But well, that is a much easier solution :)

Jaydee Lucero - 6 years, 9 months ago
Shanthanu Rai
Feb 21, 2016

2014 20132013 2013 20142014 = ( 2013 + 1 ) 20132013 2013 ( 20132013 + 10001 ) = 2013 20132013 + 20132013 2013 20132013 2013 10001 = 20132013 2013 10001 = 0 2014*20132013-2013*20142014\\=(2013+1)*20132013-2013*(20132013+10001)\\=2013*20132013+20132013-2013*20132013-2013*10001\\=20132013-2013*10001\\=0

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