Going Around The Bases

Geometry Level 1

Determine the value of cos ⁡ ( 0 ∘ ) sin ⁡ ( 9 0 ∘ ) cos ⁡ ( 18 0 ∘ ) sin ⁡ ( 27 0 ∘ ) . \cos(0^\circ) \sin(90^\circ) \cos(180^\circ) \sin(270^\circ).

− 1 -1 Undefined 0 1

Alexander Hanneken by Alexander Hanneken , 22, USA

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Cleres Cupertino
Aug 23, 2015

cos ⁡ ( 0 ° ) = 1 \cos(0°)=1
sin ⁡ ( 90 ° ) = 1 \sin(90°)=1
cos ⁡ ( 180 ° ) = − 1 \cos(180°)=-1
sin ⁡ ( 270 ° ) = − 1 \sin(270°)=-1

The product of all of these numbers is (1)(1)(-1)(-1) = 1

15 Helpful 0 Interesting 0 Brilliant 0 Confused
Hadia Qadir
Sep 6, 2015

cos (0) = 1, sin (90) = 1, cos (180 = -1, sin (270) = -1--> (1)!1)(-1)(-1)(-1) = 1

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Sunil Kumar
Sep 4, 2015

Cos(0)=1 Sin(90)=1 Cos(180)=-1 Sin(270)=-1 Cos(0)Sin(90)Cos(180)Sin(270)=1×1×-1×-1=1

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...