An algebra problem by amit bera

Algebra Level 1

Find the value of 121 x 2 − 144 y 2 121x^2 - 144y^2 when x = 1 121 , y = 1 4 x = \dfrac1{121}, y = \dfrac14 .


The answer is -8.99.

Amit Bera by amit bera , 19, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Hung Woei Neoh
May 10, 2016

x = 1 121 , y = 1 4 121 x 2 − 144 y 2 = 121 ( 1 121 ) 2 − 144 ( 1 4 ) 2 = 1 121 − 9 = 1 − 1089 121 = − 1088 121 ≈ − 8.99 x=\dfrac{1}{121},\;y=\dfrac{1}{4}\\ 121x^2 - 144y^2\\ =121\left(\dfrac{1}{121}\right)^2 - 144\left(\dfrac{1}{4}\right)^2\\ =\dfrac{1}{121} - 9\\ =\dfrac{1-1089}{121}\\ =-\dfrac{1088}{121}\\ \approx \boxed{-8.99}

1 Helpful 0 Interesting 0 Brilliant 1 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...