A calculus problem by Ankit Nigam

Calculus Level 3

Let h ( x ) = f ( x ) ( f ( x ) ) 2 + ( f ( x ) ) 3 h\left( x \right) =f\left( x \right) -{ (f\left( x \right) ) }^{ 2 }+{ (f\left( x \right) ) }^{ 3 } for every real number x. Then

PRACTICE FOR BITSAT HERE

h is increasing whenever f is increasing nothing can be said in general h is increasing whenever f is decreasing h is decreasing whenever f is increasing

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1 solution

Aalap Shah
Apr 17, 2015

Differentiate both sides of the given equation, with respect to x , using chain rule: h ( x ) = f ( x ) 2 f ( x ) f ( x ) + 3 f ( x ) 2 f ( x ) \therefore h'(x)=f'(x)-2f(x)f'(x)+3{ f(x) }^{ 2 }f'(x) h ( x ) = f ( x ) [ 1 2 f ( x ) + 3 f ( x ) 2 ] \therefore h'(x)=f'(x)[1-2f(x)+3{ f(x) }^{ 2 }] Note that the quantity in the bracket is always positive, provided f(x) is real. This is because the quadratic discriminant of: 3 x 2 2 x + 1 3x^2-2x+1 is less than zero. Thus, h'(x) and f'(x) have the same sign, implying that h(x) is increasing iff f(x) is increasing.

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