Lemons make mess

Algebra Level pending

If $l$ and $m$ are real and $l \pm m > 0$ , then the roots of the equation $(l-m)n^2 -5(l+m)n -2(l-m) = 0$ are $\text{\_\_\_\_\_\_\_\_\_\_}$ .

real and distinct none real and equal imaginary

1 solution

Ashrit Ramadurgam
Mar 20, 2016

$\Delta = b^2 - 4ac$ $=\Big( -5(l+m) \Big) ^2 -4 \Big( (l-m) \times -2(l-m) \Big)$ $=25(l+m)^2 + 8(l-m)^2$ Since $l \pm m > 0, \Delta > 0$ . Therefore, the roots are real and distinct.

Lemons make mess

1 solution

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