An algebra problem by Ashtik Mahapatra

$3^{x+3}$ = $135$ can be rewritten as $\log_{3}{135}$ = $x+3$ .

$\log_{3}{135}$ - $3$ = $x$

$\log_{3}{135}$ - $\log{3}{27}$ = $x$

$\log_{3}{5}$ = $x$

$\log_{3}{5}$ is approximately 1.47

So, $x$ = $\boxed{1.47}$

1)taking log on both sides we get (x+3) * log(3) = log(135)

2) log (135) = log (3 3 3 5) = log(5) +3 log(3)

NOTE: log 5 = log(10/2) = log(10) - log(2) = 1-.0.3010 = 0.699

4) log(135) = 0.699 + 3*(.4771) = 2.1303

5) therefore putting value of log(135) in step 1, we get (x+3) = 2.1303 / 0.4771

6) x = 1.46

Hello,

given that 3^(x+3) = 135,

by taking logarithms on both sides,

(x+3) log 3 = log 135

x+3 = (log 135) / (log 3)

x = (log 135) / (log 3) - 3 = 1.465

thanks...