But it's complex!

Algebra Level pending

Find the value of sin ⁡ − 1 ( e 2 i x − 1 2 i e i x ) \large \sin^{-1} \left(\frac{e^{2ix}-1}{2ie^{ix} }\right) at x = π 2 x=\frac\pi2 .

If the answer is A π A\pi , submit your answer as A A . [Hint:Use the eulers formula for complex numbers That is e i x = cos ⁡ x + i sin ⁡ x e^{ix}=\cos{x}+i\sin{x} ]


The answer is 0.5.

Ayush Sharma by Ayush Sharma , 20, India

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