A number theory problem by Babymathew Manoth

Number Theory Level 1

( 7 ! ) 2 ( 6 ! ) 3 = ? \large \frac{(7!)^2}{(6!)^3} =\, ?

49/720 49/90 49/180 49/360

Babymathew Manoth by Babymathew Manoth , 58, India

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1 solution

Kay Xspre
Mar 28, 2016

We expand them into 7 × 7 6 ! × 6 ! × 6 ! 6 ! × 6 ! = 49 720 \frac{7\times7}{6!}\times\frac{6!\times6!}{6!\times6!} = \frac{49}{720}

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