An algebra problem by Brijo Skylite

Algebra Level 1

What is the cube root of (-1)?

-i 1 i -1

Brijo Skylite by Brijo Skylite , 21, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

The solution is pretty simple though.

− 1 3 = − 1 ∗ − 1 ∗ − 1 3 ( S i n c e , − 1 ∗ − 1 ∗ − 1 = − 1 ) − 1 3 = − 1 \sqrt [ 3 ]{ -1 } \quad =\quad \sqrt [ 3 ]{ -1*-1*-1 } (Since,\quad -1\quad *\quad -1\quad *\quad -1\quad =\quad -1)\\ \sqrt [ 3 ]{ -1 } \quad =\quad -1

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Arulx Z
Aug 17, 2015

− 1 3 = − 1 \sqrt [ 3 ]{ -1 } =-1

Other are non-real.

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Reza Nik
Aug 8, 2015

I didn't saw any easier problem than it before.

(-1)^3= -1 -1 -1= -1

0 Helpful 0 Interesting 0 Brilliant 0 Confused

You have CUBED -1, not CUBE ROOTED it, fortunately for you, the answer was the same in both cases.

Yashwanth Manivannan - 5 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...