An algebra problem by A Former Brilliant Member

${ 9 }^{ -1/2 }\quad =\quad \frac { 1 }{ { 9 }^{ 1/2 } } \quad =\quad \frac { 1 }{ \sqrt { 9 } } \quad =\quad \frac { 1 }{ 3 } \\ \\ \\ \\{ 27 }^{ 1/3 }\quad =\quad \sqrt [ 3 ]{ 27 } \quad =\quad 3\\ \\ \\ \\\frac { 1 }{ 3 } \quad \times \quad 3\quad =\quad \boxed { 1 }$

the value of 9^-1/2=1/3. Similarly value of 27^1/3=3. therefore 3 multiplied by 1/3=1