An algebra problem by Denton Young

Algebra Level 1

A chess player played 50 games in a certain tournament. He won 26 games and drew 20% of his games. How many games did he lose?

4 14 9 19

Denton Young by Denton Young , 47, USA

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3 solutions

He won 26

he drew 20%..so, he drew 20% of 50 games

=10 games

so, games lost= 50-10-26

=50-36

=14

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Alex Delhumeau
Jun 3, 2015

(Games Lost) = (Games Neither Won Nor Drawn) = 50 − 26 − . 2 × 50 = 14 50-26-.2\times{50}=\boxed{14} .

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Denton Young
Jun 1, 2015

w = wins, d = draws, l = losses

w + d + l = 50

w = 26

d+ l = 50-26 = 24

d = 50 * 20% = 50 * 0.2 = 10

l = 24-10 = 14

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