An algebra problem by Denton Young

Algebra Level 1

A restaurant has 3 different appetizers, 4 different entrees, and 5 different desserts.

A meal contains exactly one appetizer, exactly one entree, and exactly one dessert.

How many different meals can be made?


The answer is 60.

Denton Young by Denton Young , 47, USA

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4 solutions

3 × 4 × 5 = 12 × 5 = 60 3 \times 4 \times 5 = 12 \times 5 = 60 meals

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Jingyang Tan
Jul 22, 2015

3 time 4 times 5 equals to 60

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Bryan Tj
Jul 20, 2015

3 C 1 ∗ 4 C 1 ∗ 5 C 1 = 3 ∗ 4 ∗ 5 = 60 _{3}C_{1}*_{4}C_{1}*_{5}C_{1} = 3*4*5 = 60

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Noel Lo
Jun 4, 2015

3 × 4 × 5 = 60 3\times 4\times 5 = \boxed{60} .

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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