An algebra problem by Dharani Chinta

Algebra Level 4

Let N N be any four-digit integer x 1 x 2 x 3 x 4 \overline{x_1x_2x_3x_4} , where x 1 x_1 , x 2 x_2 , x 3 x_3 , and x 4 x_4 are single-digit positive integers and x 1 0 x_1 \ne 0 .

Find the maximum value of N x 1 + x 2 + x 3 + x 4 \left \lfloor \dfrac{N}{x_1 + x_2 + x_3 + x_4} \right \rfloor , where \lfloor \cdot \rfloor denotes the floor function .


The answer is 759.

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1 solution

Juan Cruz Roldán
Oct 29, 2020

In order to get the maximun value we must divide a large number by a small one. We calculate the minimun value (4) for the sum of the 4 digits and then compare it to the maximun (36). We calculate their geometric mean 4 × 36 = 12 \sqrt{4 \times 36} = 12 . Now we choose from all the posible partitions of 12 the one whose digits concatenated form the largest number. Then we evaluate 9111 / 12 = 759 \lfloor{9111/12}\rfloor =759

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