An algebra problem by I Gede Arya Raditya Parameswara

Algebra Level 3

{ 2 x + 3 y = 5 2 x 2 + 2 x y + y 2 = 5 \begin{cases} 2x+3y=5\\ 2x^{2}+2xy+y^{2}=5\end{cases}

Let x x and y y be numbers satisfying the system of equations above.

What is the sum of all possible value of y y ?


The answer is 4.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Abhijit Dixit
Mar 4, 2017

Substitute y = 5 2 x 3 y= \frac{5-2x}{3} giving x = 1 , 2 x=1,-2 and hence y = 1 , 3 y=1,3

x can also -5,-8,-11,...

I Gede Arya Raditya Parameswara - 4 years, 3 months ago

No, counter example

for -5 both equation give different values of y

ABHIJIT DIXIT - 4 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...