An algebra problem by divyansh tripathi
Algebra
Level
pending
Let f [x] be a polynomial of degree five with leading coefficient 252 If f [2]= 3, f [3]= 8, f [4] = 15, f [5]= 24, f [6] = 35 .Then f [1]/252=?
-120
-99
99
0
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Let f(x)=252(x-2)(x-3)(x-4)(x-5)(x-6)+(x^2 - 1). f(1) = -(252)(120)