An algebra problem by Dragoș Lupușor

Using the Order of Operations, let us write this equation as $2 + (2 \div 2) = 2 + 1 = 3$ . Thus $2 + 2 \div 2 = 3$ .

BODMAS or PEMDAS: since we cannot see any parenthesis and exponents, the first operation is multiplication or division from left to right then followed by addition or subtraction from left to right

$2+2 \div 2 = 2 + 1 = \boxed{3}$

$2 + 2 ÷ 2 = 2 + 1 = \color{#69047E}{\boxed{3}}$ .