An algebra problem by Fermin Cabrieto

Algebra Level 1


The answer is 400.

Fermin Cabrieto by Fermin Cabrieto , 24, Philippines

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Fermin Cabrieto
Aug 9, 2015

(101+99)(101-99) =(200)(2) =400

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Using the usual a 2 − b 2 = ( a + b ) ( a − b ) { a }^{ 2 }-{ b }^{ 2 }=\quad (a+b)\quad (a-b) = 101 2 − 99 2 = ( 101 − 99 ) x ( 101 + 99 ) = ( 2 ) x ( 200 ) = 400 ={ 101 }^{ 2 }\quad -\quad { 99 }^{ 2 }\\ =(101-99)\quad x\quad (101+99)\\ =(2)\quad x\quad (200)\\ =400

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...