If a = 7 and b = 1 3 ,
then the number of even positive integers less than a b is ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Since a and b are both odd, then a b is odd.
Therefore, the largest even integer less than a b is a b − 1 .
Since every other positive integer less than or equal to a b − 1 is even, then the number of even positive integers less than or equal to a b − 1 (thus, less than ab) is 2 a b − 1
Nice deduction! But, why is this problem level 3?
Log in to reply
Thank you for sharing your solution. I don't set the level to my problems, it is done by the staff.
Log in to reply
Welcome Hana, and I understood the issue involved with level 1, 2 or 3! Thanks!
Problem Loading...
Note Loading...
Set Loading...