Positive lntegers

Algebra Level 3

If a = 7 a = 7 and b = 13 b= 13 ,

then the number of even positive integers less than a b ab is ?

a b 2 \frac{ab}{2} a b ab a b 1 2 \frac{ab-1}{2} ( a b ) ( a + b ) (a-b)(a+b) a b + 1 2 \frac{ab+1}{2}

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2 solutions

Mahdi Raza
Jun 2, 2020
  • odd × odd = odd \text{odd} \times \text{odd} = \text{odd}
  • The largest even integer less than a b ab is: a b 1 ab-1 because a b ab is odd
  • Since half of the numbers in that range will odd, the number of even integers will be half that = a b 1 2 = \dfrac{ab-1}{2}
Hana Wehbi
Oct 7, 2017

Since a a and b b are both odd, then a b ab is odd.

Therefore, the largest even integer less than a b ab is a b 1 ab - 1 .

Since every other positive integer less than or equal to a b 1 ab - 1 is even, then the number of even positive integers less than or equal to a b 1 ab - 1 (thus, less than ab) is a b 1 2 \frac{ab - 1}{2}

Nice deduction! But, why is this problem level 3?

Mahdi Raza - 1 year ago

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Thank you for sharing your solution. I don't set the level to my problems, it is done by the staff.

Hana Wehbi - 1 year ago

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Welcome Hana, and I understood the issue involved with level 1, 2 or 3! Thanks!

Mahdi Raza - 1 year ago

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