Fun Math Game 2

Let $c_n$ , where $n = 1,2$ be the carried-forward. In this case $c_n$ can only be $0$ or $1$ .

From $A+c_3 = 10E+F$ , the only possible case is $A=9$ , $c_3=1$ , $E=1$ and $F=0$ .

I used the below table to do the analysis of all the cases and found four cases. And the missing digit is $\boxed{3}$ .

What about 4936 +936=05872., 0 can be prefixed before the answer as there is no constraint for that... Right??

9782 + 782 = 10564

The missing digit is 3