An algebra problem by Hobart Pao

From [https://brilliant.org/wiki/gaussian-elimination/] :

A matrix is in the reduced row echelon form if it has equal dimensions and it satisfies the following

1. The leftmost non-zero element in each row is 1 (also called pivot)

2. Any column can have at most 1 pivot.

3. For any two columns $C_1$ and $C_2$ that have pivots in rows $R_1$ and $R_2$ , respectively, if pivot in $C_1$ is to the left of pivot in $C_2$ . then $R_1$ is above $R_2$ .

4. Rows that consist only zeros are in the bottom of the matrix

Now let's check that all these conditions are satisfied by matrix A

1. There is only one element which is 1 so this condition is satisfied.
2. Also, satisfied because there is only one pivot in the matrix A
3. There are only one row and column so this condition is satisfied
4. There is only one element in the matrix A so there aren't any zeros to be bottom of the matrix

All conditions are satisfied so in conclusion, the answer is $\fbox{Yes}$