An algebra problem by Hobart Pao

Algebra Level 2

Identify the correct statements regarding

( 1 + i 3 2 ) 3 \left( \dfrac{-1 + i \sqrt{3}}{2} \right)^3 and ( 1 i 3 2 ) 6 \left( \dfrac{-1 - i \sqrt{3}}{2}\right)^6

I. R e ( 1 + i 3 2 ) 3 = R e ( 1 i 3 2 ) 6 \mathscr{Re}\left( \dfrac{-1 + i \sqrt{3}}{2} \right)^3 = \mathscr{Re}\left( \dfrac{-1 - i \sqrt{3}}{2}\right)^6

II. I m ( 1 + i 3 2 ) 3 = I m ( 1 i 3 2 ) 6 \mathscr{Im}\left( \dfrac{-1 + i \sqrt{3}}{2} \right)^ 3= \mathscr{Im}\left( \dfrac{-1 - i \sqrt{3}}{2}\right)^6

Both I & II I, only II, only Neither I nor II

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Steven Chase
Jan 9, 2017

The first quantity (inside the parentheses) is equal to 1@120 deg, and the second (inside the parentheses) is equal to 1@-120 deg. Either one cubed is +1, and either one to the 6th power is +1. Therefore, the real part of either one cubed is equal to the real part of either one to the sixth. Same goes for the imaginary part. These are +1 and 0 respectively.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...