An algebra problem by Israel Sapnu Jr.

$x+2(x+1)+3(x+1)+...+10(x+1)=110$

$(x+1)+2(x+1)+3(x+1)+...+10(x+1)=111$

$(x+1)(1+2+3+...+10)=111$

$55(x+1)=111$

$x+1=\frac{111}{55}$

$x=\frac{111}{55}-1$

$x=\frac{56}{55}\approx\boxed{1.018}$

(x + 1)(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10) = 110 + 1

(x + 1) 55 = 111

x = 111/ 55 - 1 = 1.0181818181818181818181818181818