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1 solution
Simplifying ( x + y ) 2 + ( y + z ) 2 + ( x + z ) 2 we get, x 2 + y 2 + 2 x y + y 2 + z 2 + 2 y z + x 2 + z 2 + 2 x z
● 2 ( x 2 + y 2 + z 2 + x y + y z + z x )
●Now putting x 2 = ( 2 0 1 3 − y z ) , y 2 = ( 2 0 1 4 − x z ) and z 2 = ( 2 0 1 5 − x y ) .
● 2 ( 2 0 1 3 − y z + 2 0 1 4 − x z + 2 0 1 5 − x y + x y + y z + z x
● 2 ( 2 0 1 3 + 2 0 1 4 + 2 0 1 5 )
● 2 ( 6 0 4 2 )
1 2 0 8 4