An algebra problem by Kashif Khan
A man owns some balls.
On the first day, he bought some more balls, equal to double the number that he had initially.
On the second day, he bough some more balls, equal to the square of the number that he had initially.
If he gives 10 balls to his friend, he would have 0 balls remaining.
How many balls did he have initially?
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1 solution
a man initially have X balls he bought equals to the double that he had initially i.e 2X now he have 3X balls next day he bought X^2 balls and 10 balls give to the friend he have now zero it forms an quadratic equation X^2 + 3X -10 =0 which gives two answers 2 and -5 the positive one should be taken which is the right answer