An algebra problem by Kio Le

Algebra Level 1

( 1 3 ) 2 n − 1 = 3 5 \large{\left(\dfrac{1}{3}\right)^{2n-1}=3^5} What is the value of n n ?


The answer is -2.

Kio Le by Kio Le , 20, Vietnam

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1 solution

Kio Le
Feb 13, 2015

(1/3)^2n-1=3^5 =>2n-1=-5 =>2n=-4 =>n=-2

0 Helpful 0 Interesting 0 Brilliant 0 Confused

To clarify you should consider placing 2 n − 1 2n - 1 in parentheses, like so: \text {(1/3)^(2n-1)} so as to obey standard order of operations.

Caleb Townsend - 6 years, 4 months ago

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