Midas Touch

Algebra Level 3

The legendary King Midas possessed a huge amount of gold. He hid this treasure carefully in a building consisting of rooms. In each room there were a number of boxes; this number was equal to the number of rooms in the building. Each box contained a number of golden coins that equalled the number of boxes per room. When the King died, 1 box was given to the royal barber. the remainder of coins should be divided fairly between his sons. What is the max number of sons he can have?

None of these Number of rooms plus + 1 Number of rooms Number of rooms - 1

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1 solution

Kunal Jain
Mar 26, 2015

Assume the number of rooms to be x+1 Then the number of boxes in each room will also be x+1 and the number of coins in each box will also be x+1 After 1 box has been given to the royal barber, x number of rooms will have x+1 boxes and 1 room will have x boxes. Therefore, the total number of coins would be x(x+1)(x+1) + x(x+1) x(x+1)(x+1) + x(x+1) = x(x+1)[(x+1) + 1] = x(x+1)(x+2)

Sice there were x+1 number of rooms, the maximum number of sons he can have will be The number of rooms + 1

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