The Old Switcheroo

Algebra Level pending

Which would remain a function if the inputs(x) and the outputs(y) were switched? e.x. The set of points {(0,2),(5,4),(6,2)} would turn into {(2,0),(4,5),(2,6)}, (x,y) -> (y,x)

BTW brilliant.org won't allow me to use the absolute value sign or square root (can't get anything under it), so I used these: sqrt(x) = square root of x, and abv(x) = absolute value of x

{(5,0),(6,8),(2,4),(5,13)} y=sqrt(16-((13x-5)²/x²)) y=(x+3)(2x+5)(x+1) y=abv(x²-5x-3) tater tots (this is for people who don't know how to answer this, or just want to see the answer.) y=2x²(x³+(1/(2x)))

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1 solution

Logan Dapp
Oct 17, 2017

Functions are a special relationship between two quantities. Functions have to have one, no more, no less, output(y) for every input(x). To switch the input and output for equations, you just switch the x's and y's. y=2x²(x³+(1/(2x))) y=2x 5 \frac{5}{} +x x=2y 5 \frac{5}{} +y If you graph that on a graphing calculator (such as desmos.com or something) there is no place where the two lines are over each other. You can manipulate it so you get the classic equation, but I am too lazy =D

You can type the square root function and absolute function easily if you learn some basic LaTeX \LaTeX .

\sqrt{\cdot} \qquad | \cdot |

Pi Han Goh - 3 years, 7 months ago

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